4[(7x+8)-8]=2(3x+2)

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Solution for 4[(7x+8)-8]=2(3x+2) equation:


Simplifying
4[(7x + 8) + -8] = 2(3x + 2)

Reorder the terms:
4[(8 + 7x) + -8] = 2(3x + 2)

Remove parenthesis around (8 + 7x)
4[8 + 7x + -8] = 2(3x + 2)

Reorder the terms:
4[8 + -8 + 7x] = 2(3x + 2)

Combine like terms: 8 + -8 = 0
4[0 + 7x] = 2(3x + 2)
4[7x] = 2(3x + 2)

Remove brackets around [7x]
4 * 7x = 2(3x + 2)

Multiply 4 * 7
28x = 2(3x + 2)

Reorder the terms:
28x = 2(2 + 3x)
28x = (2 * 2 + 3x * 2)
28x = (4 + 6x)

Solving
28x = 4 + 6x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6x' to each side of the equation.
28x + -6x = 4 + 6x + -6x

Combine like terms: 28x + -6x = 22x
22x = 4 + 6x + -6x

Combine like terms: 6x + -6x = 0
22x = 4 + 0
22x = 4

Divide each side by '22'.
x = 0.1818181818

Simplifying
x = 0.1818181818

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